A long narrow horizontal slit lies 1 mm above a plane mirror. The interference pattern produced by the slit and its image is viewed on a screen Σ distant 1m from the slit. The wavelength of light is 600 nm. Then the distance of the first maxima above the mirror is equal to (d << D):
Text Solution
Verified by ExpertsThe correct answer is:
B
Point O is a minima Hence the first maxima will be at y = 
from O.
⇒ y = 
= 
= 0.15 mm.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
In Young’s double slit experiment using sodium light ( λ λ = 5898Å), 92 fringes are seen. If given …
If two waves represented by and
interfere at a point, the amplitude of the resulting wave will be…
Two waves being produced by two sources and . Both sources have zero phase difference and have wa…
Two interfering wave (having intensities are 9I and 4I) path difference between them is 11 λ λ . Th…
In interference if then what will be the ratio of amplitudes of the interfering wave
Two interfering waves having intensities x and y meets a point with time difference 3T/2. What will…